A particle follows a path defined by y = 8-3t^2-5t. At what time is the particle at ground level?

A particle follows a path defined by `y=8-3t^2-5t`

The variable y represents the height of the particle for a given time t. 

The particle is at ground level when y=0. For this problem, set y=0 and solve for t.

`y=-3t^2-5t+8`

`0=-3t^2-5t+8`

`0=-(3t^2+5t-8)`

`0=-(3t+8)(t-1)`

`t=1,t=-8/3`

Since time may not be negative the final answer is t=1 second.

Final Answer: The particle is at ground level at 1 second.