`f(x) = arcsin(x) + arccos(x)` Find the derivative of the function

 Recall that the derivative of a function f at a point x is denoted as f'(x).

 The given function: `f(x)= arcsin(x)+arccos(x)` has  inverse trigonometric terms.

There are basic formulas for the derivative of inverse trigonometric functions:

`d/(dx) (arcsin(u)) = ((du)/(dx))/sqrt(1-u^2)`

`d/(dx) (arccos(u)) = -((du)/(dx))/sqrt(1-u^2). `

Applying the formula in the given function:

`f'(x) =d/(dx) (arcsin(x)) +d/(dx) (arccos(x))`

`f'(x) =1/sqrt(1-x^2) + (-1/sqrt(1-x^2))`

`f'(x) =1/sqrt(1-x^2) -1/sqrt(1-x^2)`

`f'(x) =0`