How do I differentiate the natural logarithm? For example, y=3ln(6t+1)

`y=3ln(6t+1)`

To take the derivative of this, refer to formula:

`d/(dx) (ln u) = 1/u * (du)/dx `

Applying that, the derivative of the function will be:

`d/(dt)(y) = d/(dt)[3ln(6t+1)]`

`(dy)/(dt)=3d/(dt)[ln(6t+1)]`

`(dy)/(dt)=3*1/(6t+1) * d/(dt)(6t+1)`

`(dy)/(dt)=3*1/(6t+1) * 6`

`(dy)/(dt)=18/(6t+1)`

Therefore, `(dy)/(dt) = 18/(6t+1)` .

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