Friday, October 14, 2011

`lim_(x->oo)sechx` Find the limit

Given,


`lim_(x->oo)` sech(x)


to find the value of `lim_(x->oo)`sechx


we need to find the value of


`lim_(x->-oo)` sechx and `lim_(x->+oo)`sechx


so,


the value of


`lim_(x->-oo)`sechx is as x tends to negative infinity the sech(x) -> 0


and similarly as


`lim_(x->+oo)`sechx is as x tends to positive infinity the sech(x) -> 0


So,


`lim_(x->-oo)`sechx`=lim_(x->+oo)` sechx`=0`


the limit exits for`lim_(x->oo)`sechx 


and the value is`lim_(x->oo)`sechx=0

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