`log_b(27) = 3` Solve for x or b

`log_b (27) = 3`

To solve, convert this to exponential equation.

Take note that if a logarithmic equation is in the form

`y = log_b (x)`

its equivalent exponential equation is:

`x = b^y`

So converting

`log_b (27) = 3`

to exponential equation, it becomes:

`27 = b^3`

Then, factor the left side.

`3^3 = b^3`

And isolate the b by taking the cube root of both sides.

`root(3)(3^3)=root(3)(b^3)`

`3=b`

Therefore, `b = 3` .