Find the quadratic function whose graph passes through the given points. (-1,4), (0,3), (1,4).

Let us say the quadratic function is;

`y = ax^2+bx+c` where a,b and c are constants and `a!=0` .

It is given that  graph passes through (-1,4).

`4 = a(-1)^2+b(-1)+c`

`4 = a-b+c-------(1)`

Similarly by applying passing points (0,3) and (1,4) we can obtain the following equations.

`3 = a(0)^2+b(0)+c`

`3 = c------(2)`

`4 = a(1)^2+b(1)+c`

`4 = a+b+c----(3)`

`(1)+(3)`

`8 = 2a+2c`

From (2) `c = 3`

`8 = 2a+2xx3`

`a = 1`

From (3);

`4 = a+b+c`

`4 = 1+b+3`

`b = 0`

So the quadratic function is `y = x^2+3`