How is Benvolio a foil to Romeo?

Benvolio and Romeo are both Montagues, similar in age, and good friends. Where Romeo is given to intense emotions, however, Benvolio is much more level-headed. Romeo is pretty self-centered; Benvolio is not. Benvolio seeks peace; he tries to break up a fight between his house and the Capulets in Act I, Scene 1, and sttempts to prevent another such fight just before Tybalt kills Mercutio, an action that prompts Romeo to kill Tybalt. While Benvolio is constantly the voice of reason, Romeo is impulsively emotional, killing Tybalt in the street, with witnesses present. Benvolio has to tell Romeo to run afterward because Romeo seems unable to think for himself. Benvolio honestly seems like the most mature out of Romeo and all his friends; he's not interested in fighting, doesn't make the same kinds of bawdy and sexual jokes as the others do, and usually acts in a measured and calm way.

What does Macbeth mean when he says, "There is none but he/ Whose being I do fear"?

As his paranoia increases, Macbeth becomes very anxious about Banquo, as the witches told him his sons will become kings.

In the beginning of Act III, at Forres, the castle that was King Duncan's and is now Macbeth's, Banquo, who is a guest, realizes Macbeth has all that "the weird women" promised him. Also, he fears Macbeth had a hand in his own fortune: "Thou play'dst most foully for 't" (Act III, Scene 1, line 3). Then, because of the turn of events, Banquo wonders if the witches' prophecy about himself will come true.

Later, Banquo informs Macbeth that he and his son Fleance plan to ride for an hour; Macbeth extends good wishes for an enjoyable ride and urges Banquo to return for the banquet that evening.

After Banquo and his son's departure, Macbeth expresses his fear of Banquo, who heard the prophesy about him and received prophesies of his own.

To be thus is nothing, but to be safely thus—
Our fears in Banquo stick deep.
And in his royalty of nature reigns that 
Which would be feared. . . 
He hath a wisdom that doth guide his valor
To act in safety (Act III, Scene 1, lines 50-56).

When Macbeth says he fears Banquo's "being," he means he is worried that since the predictions of the witches have come true for him—even though he helped cause some of this reality—those predictions about Banquo's becoming the father of kings may also become real. Since Macbeth has no heirs, he fears he may have sold his soul to the Devil in order to make Banquo's sons kings as the witches have foretold. 

Only for them, and mine eternal jewel [his soul]
Given to the common enemy of man [the Devil to whom he has sold his soul],
To make them kings, the seeds of Banquo kings! (Act III, Scene 1, lines 71-73)

In addition, he worries Banquo may take some actions himself for his "safety." Macbeth hires two murderers and sends them to kill Banquo and his son.

Why do you think Godwin chose third person?

I would argue Godwin uses third person in his classic science fiction short story to provide emotional distance.

As the title indicates, much of the theme of the story revolves around Barton (the pilot) thinking coldly. He and the stowaway are living in a universe determined by these equations. All actions are determined by mathematical formulae, which are fundamentally third person and objective. There is (ideally) no subjective element to math. In the same sense, a third-person perspective allows Godwin to maintain emotional distance and objectivity. A first-person perspective would permit too much intimacy.

A second, related reason is to maintain tension. Readers must wait for Barton to reach his decision. They have no access to his internal processes. They don't know what he is thinking or feeling, and must wait for the decision to emerge, waiting along with Marilyn (the stowaway) to learn her fate.

How does Scout's realization of Cal's age show the disadvantages of her point of view?

On the day that Scout goes to church with Calpurnia, she learns many things. She talks to Calpurnia in a way that she had not before. She asks Calpurnia questions about her personal life.

Scout asks Calpurnia how she learned to read. Calpurnia tells Scout that Miss Maudie's aunt, Miss Buford, taught her. Miss Buford and Calpurnia had lived by Finch's Landing. Scout is shocked to hear this. Miss Maudie is quite old, which means her aunt had been born many years before even her. Scout questions Calpurnia about her age. Calpurnia gives her the story:

"I'm older than Mr. Finch, even." Calpurnia grinned. "Not sure how much, though. We started rememberin' one time, trying to figure out how old I was—I can remember back just a few years more'n he can, so I'm not much older, when you take off the fact that men can't remember as well as women" (Chapter 12).

This surprises Scout because she thinks her father is very old. She points out to Calpurnia that she looks very young despite being older than Atticus. Calpurnia explains why she thinks this is.

"Colored folks don't show their ages so fast," she said.

The story is told solely from Scout's point of view. As a child, Scout does not always see the bigger picture. She has an idea in her mind about Calpurnia. She may see her as ageless, while she views her father as being older. Scout thinks that because Calpurnia looks young that she is young. She only experiences Calpurnia in her own home. She rarely considers Calpurnia's life outside of the Finch home. She does not think about Calpurnia having an adult son or growing up with Atticus.

Penny purchases 100 tickets for her youth services group to attend a waterpark. Child admissions are $14.00 each while adult admissions are $19.00...

This question requires you to set up a system of equations.  First, you must identify your variables.  Since we want to know how many adult tickets and how many child tickets were bought, those will be our variables.  So let:

a = # of adult tickets sold and c = # of child tickets sold

The first sentence says, "Penny purchased 100 tickets..."  This will be used to make our first equation.  The total number of both adult and child tickets should be 100, so our first equation is 

`a + c = 100`

Then it says, "Child admissions are $14 each while adult admissions are $19 each."  And it states that the total cost of the tickets is $1470.  This will be used to make our second equation, which is

`19a + 14c = 1470`

There are a few ways to solve this system of equations.  We'll go through two of them below.

1) One method to solve a system is by substitution.  You must solve one equation for one of the variables, then substitute that into the second equation.  For this problem, the first equation is very easy to use to solve for a variable since the variables do not have coefficients.  So

`a + c = 100`  becomes  `c = 100 - a`

This will be substituted into our second equation like so:

`19a + 14(100 - a) = 1470`

From here you can solve the equation for a using algebra:

`19a + 1400 - 14a = 1470`

`5a + 1400 = 1470`

`5a = 70`

`a = 14`

Now this value for a can be substituted into either original equation to find the value of c.  The first equation is, again, a very easy one to use:

`(14) + c = 100`

`c = 86`

So, Penny bought 14 adult tickets and 86 child tickets.

2) This can also be solved using the elimination method.  In the elimination method, you are adding the two equations together in an effort to make one of the variables cancel out (eliminate) so that you have just one varible to solve at a time.  To make this happen, you must often multiply one (or both) of the equations by a coefficient so that a variable will eliminate.  Once again, the first equation is very useful for this.  We can choose a variable to eliminate, let's say c.  In the second equation, the coefficient of the variable c is 14.  So we will multiply the first equation by -14 in order to make those two cancel.  The second equation will look like this:

`-14(a+c=100)`

`-14a-14c=-1400`

Now we will add the two equations together to get a new single equation with just one variable.

`(-14a-14c=-1400)`

`+(19a+14c=1470)`

`5a = 70`

`a = 14`

Once again, we can take this value of a and substitute it into one of the original equations to find c.  And we will again get the value 86.

3) This system of equations can also be solved graphically. If the variables are changed to x and y, they can be graphed as lines.  The point of intersection between the two lines is the solution.

Again, the final answer is that Penny bought 14 adult tickets and 86 child tickets.

What contributions have been made by Aung San Suu Kyi?

Born to parents in politics, Aung San Suu Kyi would later be recognized for her political leadership.  After spending several years away from her birth place of Myanmar, also known as Burma, Aung San Suu Kyi returned home to find political unrest and an unjust government within her country. She soon began speaking out publicly and spent 15 years in police custody under house arrest after starting a nonviolent movement toward democracy and human rights within the country.  After her release, she was awarded a Nobel Peace Prize in 1991.  Aung San Suu Kyi was also awarded a Congressional Gold Metal from the U.S. House of Representatives.  She later held a seat in the Myanmar parliament for the National League for Democracy party.  Just recently, she was named state counsellor, which gives her great leadership power within her country. 

`y' = x(1+y)` Solve the differential equation

 An ordinary differential equation (ODE) has differential equation for a function with single variable. A first order ODE follows `(dy)/(dx)= f(x,y)` .

It can also be in a form of `N(y) dy= M(x) dx` as variable separable differential equation.

 To be able to set-up the problem as `N(y) dy= M(x) dx` , we let `y' = (dy)/(dx)` .

 The problem: `y'=x(1+y)` becomes:

`(dy)/(dx)=x(1+y)`

Rearrange by cross-multiplication, we get:

`(dy)/(1+y)=xdx`

Apply direct integration on both sides: `int (dy)/(1+y)= int xdx` to solve for the general solution of a differential equation.

For the left side, we consider u-substitution by letting:

`u= 1+y` then `du = dy`

The integral becomes:  `int(dy)/(1+y)=int(du)/(u)`

 Applying basic integration formula for logarithm:

`int(du)/(u)=ln|u|`

Plug-in `u = 1+y` on `ln|u|` , we get:

`int(dy)/(1+y)=ln|1+y|`

For the right side, we apply the Power Rule of integration: `int x^n dx = x^(n+1)/(n+1)+C`

`int x* dx= x^(1+1)/(1+1)+C`

             ` = x^2/2+C`

Combining the results from both sides, we get the general solution of the differential equation as:

`ln|1+y|= x^2/2+C`

or

`y =e^((x^2/2+C))-1`