4000 joules of heat are added to 100 g of water when its temperature is 50°C . What is the new temperature of the water?

Since heat has been added to water, its temperature will rise. The amount of heat added can be related to change in temperature by using the following relation:

heat added = mass of water x specific heat of water x (final temperature - initial temperature)

The specific heat is defined as the amount of heat required to raise the temperature of 1 g of a substance by 1 degrees Celsius. In case of water, the specific heat (denoted by c) is 4.186 J/g/K.

Thus, we can solve the problem by substituting the values of various parameters in the equation:

4000 J = 100 g x 4.186 J/g/K x (final temperature - 50)

or, final temperature - 50 = (4000)/(100 x 4.186) = 9.6

or, final temperature = 50 + 9.6 = 59.6 degrees C.