The balanced chemical reaction for this problem is:
First, we need to get how many moles of sodium bicarbonate to be neutralized.
Moles of NaHCO3 =
To get the moles of citric acid (C6H8O7) that will react with 0.15 moles of NaHCO3 =
Now we can solve for the amount of citric acid needed to completely react with sodium bicarbonate.
(1) In terms of mass:
(2) In terms of the citric acid solution:
Molarity = moles/volume of solution
Volume of solution = moles citric acid/molarity of the citric acid solution
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