A cart with a mass of 65kg is being pulled by a force of 270 N. A friction force of 83 N opposes this motion. a. Calculate the weight of the cart....

(a) The mass is 65 kg, we're under normal Earth gravity of `9.8 m/s^2` , so the weight is the product of those: `(65 kg)(9.8 m/s^2) = 637 N`
(b) The net force on the cart is the sum of four forces: gravity, the normal force which exactly cancels gravity to hold the cart on the ground, the pulling force, and friction. Because the normal force cancels gravity, the net force is just the pulling force of `270 N ` minus the friction of `83 N`, so `F = (270 N) - (83 N) = 187 N`

(c) The acceleration can be found by `F = ma` , which solved for a is `a = F/m = (187 N)/(65 kg) = 2.9 m/s^2`