A stone is thrown vertically upward with a velocity of 5 m/s. Acceleration due to gravity is 10 ms^- 2 in the downward direction. How can I...

We can use equations of motion to solve this problem.

In the given scenario, the initial velocity (u) of the stone is given as 5 m/s. The acceleration due to gravity (g) is 10 m/s^2 in the downward direction. This means that it will oppose the upward motion of the stone. This will cause the stone to slow down and ultimately come to a rest. When this happens, the velocity will be zero. After that the stone will start falling back. 

Thus, for the upward motion, final velocity (v) = 0 m/s.

Using v^2 = u^2 + 2as = u^2 + 2(-g)s

then 0^2 = 5^2 + 2(-10)s

Solving this, we get: s = -25/(-20) = 1.25 m.

The time taken to reach the highest point can be solved by:

v = u + at

or, 0 = 5 + (-10) t

or, t = -5/-10 = 0.5 s.

Thus, the stone will attain a maximum height of 1.25 m, 0.5 seconds after being thrown in the upwards direction with a velocity of 5 m/s.

Hope this helps.