Indefinite integral are written in the form of` int f(x) dx = F(x) +C`
where: f(x) as the integrand
F(x) as the anti-derivative function
C as the arbitrary constant known as constant of integration
For the given problem `int 3^x dx ` has a integrand in a form of exponential function.
There is basic integration formula for exponential function:
`int a^u du = a^u/(ln(a)) +C` where a is a constant.
By comparison, `a = 3` ,` u = x` , and `du =dx` .
Applying the formula, we get:
`int 3^x dx = 3^x/(ln(3)) +C`
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