`y=log_4(5x + 1)`
The derivative formula of a logarithm is:
`d/(dx) [log_a (u)] = 1/(ln(a) * u) * (du)/(dx)`
Applying that formula, the derivative of the function will be:
`(dy)/(dx) = d/(dx)[ log_4(5x+1)]`
`(dy)/(dx) =1/(ln(4) * (5x+1))* d/(dx) (5x+1)`
`(dy)/(dx) =1/(ln(4) * (5x+1)) * 5`
`(dy)/(dx) =5/((5x+1)ln(4))`
Therefore, the derivative of the function is `(dy)/(dx) =5/((5x+1)ln(4))` .
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